SOLUTION: Tickets to a school concert were priced at $50, $150, and $250. The $150 tickets sold were twice as many as $250 ones. $50 tickets were 4 times as many as $250 and $150 tickets com

Algebra ->  Customizable Word Problem Solvers  -> Coins -> SOLUTION: Tickets to a school concert were priced at $50, $150, and $250. The $150 tickets sold were twice as many as $250 ones. $50 tickets were 4 times as many as $250 and $150 tickets com      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 1093376: Tickets to a school concert were priced at $50, $150, and $250. The $150 tickets sold were twice as many as $250 ones. $50 tickets were 4 times as many as $250 and $150 tickets combined together. If the gross receipts at the gate totalled $69,000, how many of each ticket were sold?
Found 2 solutions by josgarithmetic, richwmiller:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
x, how many $50 tickets
y, how many $150's
z, how many $250's

The description directly gives this system:
system%28y%2Fz=2%2Cx=4%28y%2Bz%29%2C50x%2B150y%2B250z=69000%29


.
.
.

Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
f=$50 tickets
o=$150 tickets
t=$250 tickets
o=2t
f=4(t+o)
50f+150o+250t=69000
5f+15o+25t=6900
now let's substitute
20(t+o)+15o+25t=6900
20t+20o+15o+25t=6900
35o+45t=6900
35*2t+45t=6900
115t=6900
t=6900/115
t=60
o=120
f=4(180)=720
check
50*720+150*120+60*250=69000
69000=69000
ok