SOLUTION: please help me solve this question it is supposed to be represented in interval notion x^2<4x+12 I tried moving everything to the left and then factorized and I received (x-6)

Algebra ->  Inequalities -> SOLUTION: please help me solve this question it is supposed to be represented in interval notion x^2<4x+12 I tried moving everything to the left and then factorized and I received (x-6)      Log On


   

Question 1093239: please help me solve this question
it is supposed to be represented in interval notion
x^2<4x+12
I tried moving everything to the left and then factorized and I received (x-6) (x+2)<0 and as an answer In interval notion I wrote (-2,6) u (6,infinity)
Found 2 solutions by josgarithmetic, greenestamps:
Answer by josgarithmetic(39623) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2%3C4x%2B12
x%5E2-4x-12%3C0
%28x-6%29%28x%2B2%29%3C0, which tells you the left side must be LESS THAN 0.
The ROOTS for the expression on left are -2 and +6.
The expression will be LESS THAN 0 for x between -2 and +6, excluding them. (Check that for yourself).

-2%3Cx%3C6
OR
(-2, 6), in interval notation

Answer by greenestamps(13203) About Me  (Show Source):
You can put this solution on YOUR website!

Your process is fine; but your conclusion is not right....

If you determined the solution set algebraically, then there is something wrong with your work there.

It is easy to see what the solution set should be if you graph the equation corresponding to your inequality.

y = (x-6)(x+2):

graph%28300%2C200%2C-5%2C10%2C-50%2C50%2C%28x-6%29%28x%2B2%29%29

On what interval(s) is the function value less than 0?