SOLUTION: Two trains, one traveling twice the speed of the other, start st the same time from stations which are 306km apart and travel towards each other. In 3 hours, the trains pass each o
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Question 1093214: Two trains, one traveling twice the speed of the other, start st the same time from stations which are 306km apart and travel towards each other. In 3 hours, the trains pass each other. Frind the rate of each train Found 2 solutions by Boreal, greenestamps:Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! slower train at x kph
faster at 2x kph
total closing speed is their sum or 3x kph
in 3 hours, they pass so 3x kph* 3h units are km=9x km=306 km
x km=34 km
2x=68 km
In 3 hours the slower train travels 102 km and the faster 204 km.
the slower train travels at 34 kph and the faster at 68 kph.
But let's see if a more informal solution makes sense to you.
The stations are 306km apart; one train travels twice as fast as the other. That means that, at the time the trains pass each other, the faster train has covered 2/3 of the distance and the slower train has covered 1/3 of the distance.
2/3 of the 306km for the faster train is 204km; since both trains traveled for 3 hours before they passed each other, the speed of the faster train is 204/3 = 68km/hr. And then the speed of the slower train is half of that, or 34km/hr.
