Question 1093203: Find three consecutive odd integers such tha three times the middle integer is 11 more than the sum of the first and third integers Found 2 solutions by rothauserc, greenestamps:Answer by rothauserc(4718) (Show Source):
You can put this solution on YOUR website! three consecutive odd integers x, x+2, x+4
:
3(x+2) = x +x+4 + 11
:
3x +6 = 2x +15
:
x = 9
:
*************************************************
the three consecutive odd integers are 9, 11, 13
*************************************************
:
You can put this solution on YOUR website! To help follow the reasoning I use for my method of solving the problem, let's call the three numbers A, B, and C.
For three consecutive odd integers, the middle number is equal to the average of the first and last numbers.
That means that twice the middle number is equal to the sum of the first and last numbers.
So if three times the middle number is 11 more than the sum of the first and last, then the middle term must be 11.
