SOLUTION: In a bowl there are some nickels, dimes and quarters. There are 5 nickels for every 6 dimes for every 3 quarters. There are 98 coins total in the bowl. What is the value of the mon

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: In a bowl there are some nickels, dimes and quarters. There are 5 nickels for every 6 dimes for every 3 quarters. There are 98 coins total in the bowl. What is the value of the mon      Log On


   

Question 1093107: In a bowl there are some nickels, dimes and quarters. There are 5 nickels for every 6 dimes for every 3 quarters. There are 98 coins total in the bowl. What is the value of the money in the bowl?
Answer by greenestamps(13203) About Me  (Show Source):
You can put this solution on YOUR website!

Stated in different words, the ratio of nickels to dimes to quarters is 5:6:3.

So call the number of nickels 5x, the number of dimes 6x, and the number of quarters 3x. That is nearly always the best way to start working a problem that gives you ratios like that.

Now, since the total number of coins is 98, you have
5x%2B6x%2B3x+=+98
It should be easy to solve that equation for x and thus determine the number of each type of coin.