Question 1093106:
A person opens his wallet and finds that all the bills are $1 bills, $5 bills, or $10 bills. There are 35
bills in this person's wallet. There are 2
more $5 bills than $1 bills. If the total amount of bills is $228
,
how many $10 bills does this person have?
Found 2 solutions by josgarithmetic, greenestamps:
Answer by josgarithmetic(39630)   (Show Source):
Answer by greenestamps(13209)  (Show Source):
You can put this solution on YOUR website!
Let x be the number of $1 bills.
Since the number of $5 bills is 2 more than the number of $1 bills, the number of $5 bills is x+2.
The total number of $1 and $5 bills is now
and, since the total number of bills is 35, the number of $10 bills is
Now you have expressions in terms of a single variable x for the numbers of $1, $5, and $10 bills. Use those expressions to write an expression for the total value of all the bills -- $1 for each of the $1 bills, $5 for each of the $5 bills, and $10 for each of the $10 bills. Finally, since you know the total value of all the bills is $228, write and solve the equation that says so.
I'll let you finish from there, to get some practice.
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