SOLUTION: Jim started with an empty piggy bank.Each day, he put a penny, a dime and a quarter into his piggy bank. He kept this up until the bank contained and exact number of dollars, not s

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Question 1092998: Jim started with an empty piggy bank.Each day, he put a penny, a dime and a quarter into his piggy bank. He kept this up until the bank contained and exact number of dollars, not s penny more or less, how many days did this take, and how many dollars did the bank finally contain?
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
The amount of many Jim put in his Piggy bank each day, in cents, is
1%2B10%2B25=36
After n days, with n being a positive integer,
Jim had 36n cents in his piggy bank,
and that was exactly d dollars, with d being a positive integer.
Those d dollars were exactly 100d cents.
At that point it was true that 36n=100d .
If we factor the numbers we know, we can write that equation as
4%2A9%2An=4%2A25%2Ad ---> 9%2An=25%2Ad .
As 9 and 25 have no common factors other than 1 ,
and n and d are positive integers,
n must be a multiple of 25 ,
and the first time that could happen it would be after n=highlight%2825%29 days.
At that point, Jim's piggy bank would have held
4%2A9%2A25cents=900cents=highlight%289dollars%29 .