Question 1092875: three times the age of Felicia is four more than Asare. in three years, the sum of their ages will be 30years. find their present ages.
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! let f = F's present age
let a = A's present age
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Write an equation for each statement
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"three times the age of Felicia is four more than Asare."
3f = a + 4
a = 3f - 4
"in three years, the sum of their ages will be 30years."
(f+3) + (a+3) = 30
f + a + 6 = 30
subtract 6 from both sides
f + a = 24
find their present ages.
replace a with (3f-4)
f + (3f -4) = 24
4f - 4 = 24
4f = 24 + 4
4f = 28
f = 28/4
f = 7 yrs is F's present age
then, using the 1st equation replace f with 7
a = 3(7) - 4
a = 17 yrs is A's present age
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Check this, find the their sum in 3 yrs
10 + 20 = 30
4f = 24 + 4
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