You can put this solution on YOUR website! 1. 5(x - 2)^2=3
Divide both sides by 5 to get:
(x-2)^2 = 3/5
Take the square root to get:
x-2 = sqrt(3/5) or x-2 = -sqrt(3/5)
x = 2 + (sqrt(15)/5 or x=2-(sqrt(15)/5)
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2. Find the x-intercepts. y = x^2 + 3x - 8
Let y = 0 and solve for x:
x^2+3x-8 = 0
x = [-3 +- sqrt(9-4*-8)]/2
x = [-3 +- sqrt(41)]/2
x = (-3+sqrt(41)] or x = [-3-sqrt(41)]
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3. Find the axis of symmetry. "y = x^2 - 5x + 10"
x^2-5x+10 = y
x^2-5x+? = y-10+?
x^2-5x+(5/2)^2 = y-10 + (5/2)^2
(x+(5/2))^2 = y-(15/4)
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Axis of symmetry: x=-5/2
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Cheers,
Stan H.
4. Solve. (x – 3)^2 = 6
Comment: Follow the same procedure
used in problem #1.
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Cheers,
Stan H.
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