Question 1092795: There are 44 coins in a purse that contains nickles, dimes, and quarters. There are twice as many dimes as quarters and 4 more nickles than quarters. How many coins of each type are in the purse?
Found 3 solutions by ankor@dixie-net.com, ikleyn, MathTherapy:
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! There are 44 coins in a purse that contains nickles, dimes, and quarters.
n + d + q = 44
There are twice as many dimes as quarters
q = 2d
divide both sides by 2
d = .5q
and 4 more nickles than quarters.
q = n + 4
subtract 4 from both side
n = q - 4
How many coins of each type are in the purse?
In the first equation, replace d with .5q and replace n with (q - 4)
(q-4) + .5q + q = 44
Combine like terms add 4 to both sides
2.5q = 48
q = 48/2.5
q = 19.2!! Something is wrong with this problem; this has to be an integer!
Answer by ikleyn(52879)  (Show Source):
You can put this solution on YOUR website! .
Let Q be the number of quarters.
Then the number of dimes is 2Q, and the number of nickels is Q+4.
Collect all coins:
Q + 2Q + (Q+4) = 44.
Simplify and solve for Q:
4Q + 4 = 44 ====> 4Q = 44-4 = 40 ====> Q =  = 10.
Answer. 10 quarters, 2*10 = 20 dimes and 10+4 = 14 nickels.
Solved.
Answer by MathTherapy(10556)  (Show Source):
You can put this solution on YOUR website!
There are 44 coins in a purse that contains nickles, dimes, and quarters. There are twice as many dimes as quarters and 4 more nickles than quarters. How many coins of each type are in the purse?
Correct answer: 
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