Question 1092736: A researcher is investigating a specimen of bacteria. She finds that the original
1000 bacteria grew to 2,048,000 in 60 hours. How fast does the bacteria (a)
double? (b) quadruple?
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Answer by rothauserc(4718)   (Show Source):
You can put this solution on YOUR website! N(t) = No * e^(r * t), where N(t) is population after time t, No is original population, r is growth rate, t is time
:
take natural log of both sides of =
:
ln(N/No) = r * t
:
r = ln(N/No) / t = ln(2,048,000/1000) / 60 = 0.1271
:
t = ln(N/No) / r
:
a) t = ln(2000/1000) / 0.1271 = 5.4536 hours
:
b) t = ln(4000/1000) / 0.1271 = 10.9071 hours
:
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