SOLUTION: A person has four times as many nickels as dimes. If the total face value of these coins is $3.90, how many of each type of coin does this person have?
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Question 1092700: A person has four times as many nickels as dimes. If the total face value of these coins is $3.90, how many of each type of coin does this person have?
To solve this problem, group (MENTALLY) all the coins in sets containing 4 nickel and one dime each.
Each set (group) of coins then is worth 4*5+10 = 30 cents.
Hence, the number of such groups is = 13.
From this point, can you complete the solution on your own ?
