SOLUTION: A cargo plane flew to the maintenance facility and back. It took one hour less time to get there than it did to get back. The speed on the trip there was 220 miles per hour. The sp

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Question 1092699: A cargo plane flew to the maintenance facility and back. It took one hour less time to get there than it did to get back. The speed on the trip there was 220 miles per hour. The speed on the way back was 200 miles per hour. How many hours did the trip there take.
Found 2 solutions by josmiceli, MathTherapy:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +d+ = the one-way distance traveled
Let +t+ = time in hrs to get back
Equation for going there:
(1) +d+=+220%2A%28+t+-+1+%29+
Equation to get back:
(2) +d+=+200t+
---------------------------
Set (1) = (2)
+200t+=+220%2A%28+t+-+1+%29+
+200t+=+220t+-+220+
+20t+=+220+
+t+=+11+
and
+t+-+1+=+10+
The trip there took 10 hrs
----------------------------
check:
(2) +d+=+200%2A11+
(2) +d+=+2200+ mi
and
(1) +d+=+220%2A%28+t+-+1+%29+
(1) +d+=+220%2A10+
(1) +d+=+2200+ mi
OK

Answer by MathTherapy(10549) About Me  (Show Source):
You can put this solution on YOUR website!

A cargo plane flew to the maintenance facility and back. It took one hour less time to get there than it did to get back. The speed on the trip there was 220 miles per hour. The speed on the way back was 200 miles per hour. How many hours did the trip there take.
Let the time it took to get to the facility be T
Then time it took to return = T + 1
We then get the following DISTANCE equation: 220T = 200(T + 1)
220T = 200T + 200
220T - 200T = 200
20T = 200
T, or time taken to get to facility = highlight_green%28matrix%281%2C4%2C+200%2F20%2C+%22=%22%2C+10%2C+hours%29%29