SOLUTION: what is the gradient of the line perpendicular to 5x-20y+9=0? and... what is the equation of the line perpendicular to 5x-20y+9=0 and passing through the point (1,-2)? answer in

Algebra ->  Coordinate-system -> SOLUTION: what is the gradient of the line perpendicular to 5x-20y+9=0? and... what is the equation of the line perpendicular to 5x-20y+9=0 and passing through the point (1,-2)? answer in      Log On


   

Question 1092591: what is the gradient of the line perpendicular to 5x-20y+9=0?
and... what is the equation of the line perpendicular to 5x-20y+9=0 and passing through the point (1,-2)? answer in general form
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Convert to slope-intercept form to get the slope(gradient),
20y=5x%2B9
y=%285%2F20%29x%2B9%2F20
y=x%2F4%2B9%2F20
m%5B1%5D=1%2F4
.
.
.
Parallel lines have identical slopes so,
m%5B2%5D=1%2F4
Using the point slope form of a line,
y-%28-2%29=%281%2F4%29%28x-1%29
y%2B2=%28x-1%29%2F4
4y%2B8=x-1
highlight%28x-4y-9=0%29