Question 109256: Factor completely.
5y^5 + 135y^2
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! :
5y^5 + 135y^2
:
Factor out 5y^2 and you have:
5y^2(y^3 + 27)
:
Can you recognize the "Sum of Cubes" in this?
Use special factoring to factor (y^3 + 27):
:
(5y^2)(y + 3)(y^2 - 3y + 9)
:
If you are not familiar with this, look up "Sum of Cubes" or "Difference of Cubes"
in the index of your book and learn it.
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