SOLUTION: A tank at a marine exhibit contains 8000 liters of sea water. The sea water is 7.5% salt. How many liters of fresh water must be added to the tank so that the mixture’s concentrati
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Question 1092494: A tank at a marine exhibit contains 8000 liters of sea water. The sea water is 7.5% salt. How many liters of fresh water must be added to the tank so that the mixture’s concentration is reduced to 7% salt? Answer by ikleyn(52943) (Show Source):
The fact that the sea water is 7.5% salt means that each liter contain 75 gram of salt.
Then 8000 liters of sea water contain 8000*75 = 600000 gram of salt.
In order to have concentration of 7% (or 70 gram of salt per liter) with this amount of salt, your volume of water must be
V = = 8571.4 liters.
So, you need to add 8571.4 - 8000 = 571.4 liters of fresh water.
Solved.
There are many ways to solve this problem, but this one is, probably, simplest.
It allows you to solve the problem without using equations (using the ratios only).
