SOLUTION: MO bisects <LMN, m<LMO = 6x - 27 and m<NMO = 2x+33 solve for X and find m<LMN

Algebra ->  Angles -> SOLUTION: MO bisects <LMN, m<LMO = 6x - 27 and m<NMO = 2x+33 solve for X and find m<LMN      Log On


   

Question 1092423: MO bisects
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Since MO is the bisector,
NMO=LMO
6x-27=2x%2B33
4x=60
Then solve for LMN,
LMN=2%282x%2B33%29
LMN=4x%2B66
You can substitute without solving for x.
LMN=60%2B66