Question 1092304: 4 sin 2theta = 3 cos theta
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! 4 sin 2theta = 3 cos theta
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If you mean
4sin(2theta) = 3cos(theta)
Use sin(2t) = 2sin(t)*cos(t)
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8sin(t)cos(t) = 3cos(t)
8sin(t)cos(t) - 3cos(t) = 0
cos(t)*(8sin(t) - 3) = 0
cos(t) = 0
t = pi/2 + n*pi, n = any integer
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8sin(t) - 3 = 0
sin(t) = 3/8
t = asin(3/8) + n*2pi
t = pi - asin(3/8) + 2n*pi
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