Question 1092099: The Fox TV network is considering replacing one of its prime-time crime investigation shows with a new family-oriented comedy show. Before a final decision is made, network executives commission a sample of 400 viewers. After viewing the comedy, 200 indicated they would watch the new show and suggested it replace the crime investigation show.
a. Estimate the value of the population proportion. (Round the z-values to 2 decimal places. Round your answer to 3 decimal places.)
Population proportion ______?
b.
Develop a 98% confidence interval for the population proportion. (Use z Distribution Table.) (Round the z-values to 2 decimal places. Round your answers to 3 decimal places.)
Confidence interval ____ and _____ ?
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! The population proportion estimate is 200/400 or 0.50. The sample is the best estimate available.
98%CI interval width is z(0.99)*sqrt {p*(1-p)/n}
+/-2.33*0.5/sqrt(n), where n=400, so it is +/-2.33*0.5/20=+/-0.058. The interval is on both sides of the sample proportion mean.
(0.442, 0.558).
The basic rule here is 1/sqrt (n) is about the error so this is 1/ sqrt(400) or 1/20 or 0.05.
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