SOLUTION: Write a​ slope-intercept equation for a line passing through the point left parenthesis 5 comma negative 4 right parenthesis(5,−4) that is parallel to the line 5 x plus
Algebra ->
Linear-equations
-> SOLUTION: Write a​ slope-intercept equation for a line passing through the point left parenthesis 5 comma negative 4 right parenthesis(5,−4) that is parallel to the line 5 x plus
Log On
Question 1092082: Write a slope-intercept equation for a line passing through the point left parenthesis 5 comma negative 4 right parenthesis(5,−4) that is parallel to the line 5 x plus 6 y equals 75x+6y=7. Then write a second equation for a line passing through the point left parenthesis 5 comma negative 4 right parenthesis(5,−4) that is perpendicular to the line 5 x plus 6 y equals 75x+6y=7. Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! 5x+6y=7
6y=-5x+7
y=-(5/6)x+(7/6); the slope is -5/6
now use point slope formula y-y1=m(x-x1), m slope, (x1, y1) point
y+4=(-5/6)(x-5)
y+4=(-5x/6)+(25/6)
y=(-5x/6)+(1/6)
=====
The perpendicular line has a negative reciprocal slope or 6/5.
y+4=(6/5)(x-5)
y+4=(6x/5)-6
y=(6x/5)-10
