Question 1092077: Jill has a swimming pool in her backyard. It is shaped like a rectangle and measures approximately 16.3 feet wide and 26.2 feet long. It is an average of 5 feet deep. During a few hot weeks during the summer, some water evaporates from the pool, and Jill needs to add 8 inches of water to the depth of the pool, using her garden hose. Although her water pressure varies, the water flows through Jill’s garden hose at an average rate of 10 gallons/minute.
Convert the dimensions of the pool to meters. Round all meter measurements to one decimal place (nearest tenth of a meter).
How many liters will Jill need to add to her pool to return the water level to its original depth? How many gallons of water is this? Reminder: Volume = Length x Width x Depth
How long will Jill need to run the hose? Express your answer in hours and minutes.
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! The pool is 4.955 m wide and 7.965 m long, or 5.0 m x 8.0 m
Depth is 1.5 m
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She adds water to increase the depth 0.2 m.
Volume of pool at full depth is 60 m^3, 5*8*1.5
Volume of pool when at 1.3 m deep is 52 m^3.
She needs to replace 8 m^3 of water, and that is 8m^3*100 cm/m*100 cm/m*100 cm/m=8,000,000 cm^3
There are 1000 cm^3 per liter, so this is 8000 liters
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The hose runs at 10 gallons a minute or 37.9 liters/minute
8000 liters/37.9 liters/minute = 211.08 minutes or 3h31m
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