SOLUTION: Five years ago,David was three times as old as his son,Mike.Five years from now,David's age will be twice his son's age.Find their present ages. emergency

Algebra ->  Customizable Word Problem Solvers  -> Age -> SOLUTION: Five years ago,David was three times as old as his son,Mike.Five years from now,David's age will be twice his son's age.Find their present ages. emergency      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 1092061: Five years ago,David was three times as old as his son,Mike.Five years from now,David's age will be twice his son's age.Find their present ages.

emergency
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Five years ago,
D-5=3%28M-5%29
D-5=3M-15
1.D-3M=-10
Five years from now,
D%2B5=2%28M%2B5%29
D%2B5=2M%2B10
2.D-2M=5
Subtract 1 from 2,
D-2M-D%2B3M=5-%28-10%29
M=15
Use either equation to solve for D.