SOLUTION: for sin a= -3/5 with terminal side in QIII and tan b= -5/12 with terminal side in QIV, find cos(a - b)

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Question 1091964: for sin a= -3/5 with terminal side in QIII and tan b= -5/12 with terminal side in QIV, find cos(a - b)
Answer by Alan3354(69443) About Me  (Show Source):
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for sin a= -3/5 with terminal side in QIII and tan b= -5/12 with terminal side in QIV, find cos(a - b)
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Find the cos(a) and cos(b), then sin(a) and sin(b)
Then, cos(a-b) = cos(a)*cos(b) + sin(a)*sin(b)