SOLUTION: The third term of an arithmetic sequence is 8 and the sixth term is 2. Find the 30th term

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Question 1091923: The third term of an arithmetic sequence is 8 and the sixth term is 2. Find the 30th term
Found 2 solutions by ikleyn, Fombitz:
Answer by ikleyn(52788) About Me  (Show Source):
You can put this solution on YOUR website!
.
The third term of an arithmetic sequence is 8 and the sixth term is 2. Find the 30th term
~~~~~~~~~~~~~~~~~

a%5B3%5D = 8 = a%5B1%5D+%2B+2d.   (1)   (a%5B1%5D is the first term of the AP)

a%5B6%5D = 2 = a%5B1%5D+%2B+5d.   (2)   (d is the common difference of the AP)


Subtract eqn(1) from eqn(2). You will get

5d - 2d = 2 - 8,   or   3d = -6.   Hence, d = -6%2F3 = -2.


Now a%5B30%5D = a%5B1%5D+%2B+29d = %28a%5B1%5D%2B2d%29 + 27d = a%5B3%5D+%2B+27d = 8 + 27*(-2) = 8 - 54 = -46.


Answer.  a%5B30%5D = -46.

Solved.

To confirm my solution, I prepared this Table in Excel on my computer.

n    a%5Bn%5D
---------------

1	         I do not need the terms a%5B1%5D and a%5B2%5D,
2	         so I left these cells empty.
3	8
4	6
5	4
6	2
7	0
8	-2
9	-4
10	-6
11	-8
12	-10
13	-12
14	-14
15	-16
16	-18
17	-20
18	-22
19	-24
20	-26
21	-28
22	-30
23	-32
24	-34
25	-36
26	-38
27	-40
28	-42
29	-44
30	-46


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There is a bunch of lessons on arithmetic progressions in this site:
    - Arithmetic progressions
    - The proofs of the formulas for arithmetic progressions
    - Problems on arithmetic progressions
    - Word problems on arithmetic progressions
    - Mathematical induction and arithmetic progressions
    - One characteristic property of arithmetic progressions
    - Solved problems on arithmetic progressions


Also,  you have this free of charge online textbook in ALGEBRA-II in this site
    - ALGEBRA-II - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Arithmetic progressions".

Save the link to this textbook

https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson

into your archive and use when it is needed.



Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
a%5Bn%5D=a%5B1%5D%2B%28n-1%29d
So,
a%5B3%5D=a%5B1%5D%2B%283-1%29d
1.8=a%5B1%5D%2B2d
and
a%5B6%5D=a%5B1%5D%2B%286-1%29d
2.2=a%5B1%5D%2B5d
Subtract 1 from 2,
a%5B1%5D%2B5d-a%5B1%5D-2d=2-8
3d=-6
d=-2
Now use either equation to solve for a%5B1%5D.
Then solve for,
a%5B30%5D=a%5B1%5D%2B%2830-1%29%28-2%29
a%5B30%5D=a%5B1%5D%2B29%28-2%29
a%5B30%5D=a%5B1%5D-58