SOLUTION: The sum of squares of two consecutive positive numbers is 41. Find the two numbers

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Question 1091834: The sum of squares of two consecutive positive numbers is 41. Find the two numbers

Found 3 solutions by Fombitz, Alan3354, MathTherapy:
Answer by Fombitz(32388)   (Show Source):
You can put this solution on YOUR website!

Solve for N then find N+1.

Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website!
4 & 5
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41/2 = 20.5
=~ 4.5
--> 4 & 5
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There's a hard way, but why bother?
x^2 + (x+1)^2 = 41
Work that out if you like.

Answer by MathTherapy(10552)   (Show Source):
You can put this solution on YOUR website!

The sum of squares of two consecutive positive numbers is 41. Find the two numbers

One number MUST be less than 7 since . It can't be 5 & 6 since their squares total more than 41, so it must be 4 & 5.
If you wish not to go through all of that, then do the following:
Let smaller INTEGER be S
Then larger is S + 1
We then get:

Complete the solution for S, the smaller integer.
Add 1 to S to get the larger integer.