SOLUTION: For the transformation T, write the inverse T<sup>-1</sup>. T: (x, y) --> ( 2x, y + 5) T<sup>-1</sup>: (x, y)--> A.) (x - 2, y - 5) B.) (½x, y - 5) C.) (2x - 1, y + 4)

Algebra ->  Formulas -> SOLUTION: For the transformation T, write the inverse T<sup>-1</sup>. T: (x, y) --> ( 2x, y + 5) T<sup>-1</sup>: (x, y)--> A.) (x - 2, y - 5) B.) (½x, y - 5) C.) (2x - 1, y + 4)       Log On


   



Question 1091733: For the transformation T, write the inverse T-1.
T: (x, y) --> ( 2x, y + 5)
T-1: (x, y)-->
A.) (x - 2, y - 5)
B.) (½x, y - 5)
C.) (2x - 1, y + 4)
Please explain. Thank you.

Found 2 solutions by Fombitz, Edwin McCravy:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
T takes the x value and doubles it and adds 5 to the y value.
So T's inverse, would take half of the x value and subtract 5 from the y value.

Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
For the transformation T, write the inverse T-1.
T: (x, y) --> (2x, y + 5)
T-1 (x, y)-->
A.) (x - 2, y - 5)
B.) (½x, y - 5)
C.) (2x - 1, y + 4)
The inverse of T, written T-1, does the exact opposite to
the coordinates as T does to them.

Transform T changes x to 2x, which is to double the first coordinate.

The opposite of doubling the first coordinate is halving the first 
coordinate, so T-1 takes x to ½x

Transform T also takes y to y+5, which is adding 5 to the second coordinate.

The opposite of adding 5 to the second coordinate is subtracting 5 from
the second coordinate, so T-1 takes y to y-5.  

Therefore,

T-1: (x, y)--> (½x, y-5)

Correct answer is B.  

Edwin