SOLUTION: F(x) = x^2-4 and G(x) =square root x Explain why GoF does not exist.

Algebra ->  Functions -> SOLUTION: F(x) = x^2-4 and G(x) =square root x Explain why GoF does not exist.      Log On


   

Question 1091723: F(x) = x^2-4 and G(x) =square root x
Explain why GoF does not exist.
Found 2 solutions by rothauserc, ikleyn:
Answer by rothauserc(4718) About Me  (Show Source):
You can put this solution on YOUR website!
GoF = square root(x^2 -4)
:
GoF is not defined for values of x, where -2 < x < 2 because the square root of a negative number is not defined over the Real numbers
:

Answer by ikleyn(52921) About Me  (Show Source):
You can put this solution on YOUR website!
.
GoF(x) does not exist at -2 < x < 2.

But it DOES exist at all other x.