SOLUTION: Please help me with this problem. x+5 (x^2+10x+25 10x) ---- / --------- * ----------- x+10 (x^2+10x x^2+15x+50) This problem has me so con

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Please help me with this problem. x+5 (x^2+10x+25 10x) ---- / --------- * ----------- x+10 (x^2+10x x^2+15x+50) This problem has me so con      Log On


   



Question 109172This question is from textbook
: Please help me with this problem.
x+5 (x^2+10x+25 10x)
---- / --------- * -----------
x+10 (x^2+10x x^2+15x+50)
This problem has me so confused, I don't know what to do with it.
Thank you
This question is from textbook

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
Please help me with this problem.
x+5 (x^2+10x+25 10x)
---- / --------- * -----------
x+10 (x^2+10x x^2+15x+50)



x+5 (x^2+10x+25 10x)
---- / --------- * -----------
x+10 (x^2+10x x^2+15x+50)

I hope you need to write your problem this way:

now we can fator %28x%5E2%2B10x%2B25%29 like this:
+x%5E2%2B5x+%2B+5x+%2B25%29...group first two terms and second two terms:
....substitute this in previous expression:

now we can fator , and factor this %28x%5E2%2B10x%29=+x%28x%2B10%29 substitute both in previous expression:

in denominator you can cancel x and x%2B5

...multiply terms in denominator

....now product of inner and outer terms

%28%28x%2B5%29%28x%2B10%29%28x%2B10%29%29%2F%2810%28x%2B5%29%28x+%2B+10%29%29....cancel x%2B5 and x+%2B+10

%28x%2B10%29%2F10....


Or, if you need to write your problem like this:



now we can fator this:
x%5E2%2B10x=+x%28x+%2B+10%29....
and this:x%5E2%2B10x%2B25=%28x%2B5%29%28x%2B5%29....
and this: %28x%5E2%2B15x%2B50%29=+%28x%2B10%29%28x%2B5%29....
now substitute it in previous expression:
...cancel x%2B10 and x%2B5

10x%2Ax%2F%28x%2B10%29%28x%2B5%29%28x%2B5%29%29+%29
10x%5E2%2F%28x%2B10%29%28x%2B5%29%28x%2B5%29%29+%29