SOLUTION: It is now between 9am and 10 o'clock am. In 4 minutes, the hour hand of a clock will be directly opposite the position occupied by the minute hand 3 minutes ago. What time is it?

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Question 1091616: It is now between 9am and 10 o'clock am. In 4 minutes, the hour hand of a clock will be directly opposite the position occupied by the minute hand 3 minutes ago. What time is it?
Answer by ikleyn(52824) About Me  (Show Source):
You can put this solution on YOUR website!
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Let the current time under the question be 9 hours and "t" minutes, where t is the real number, so t can be fraction of minutes and seconds.


The minute hand is at angular position  of  %28t%2F60%29%2A2pi  radians, counting from it vertical position at 9:00 am.

     *** Minute hand makes its full revolution of  2pi radians in 60 minutes. ***


The hour hand at this moment is at the angular position  %283%2F4%29%2A2pi+%2B+%281%2F12%29%2A%28t%2F60%29%2A2pi radians, counting from its vertical position at midnight.

     *** Hour hand has the angular velocity 12 times less than the minute hand: it is 12 times slower. ***


Three minutes ago the minute hand was in position of  %28t%2F60%29%2A2pi+-+%283%2F60%29%2A2pi  radians.


In four minutes the hour hand will be in position of   radians.


Therefore, the governing equation is 


%28t%2F60%29%2A2pi+-+%283%2F60%29%2A2pi = .


          The major part is done: the equation/the model is set up.

          The rest is just arithmetic. 


As the first step, cancel 2pi in both sides and multiply by 60 both sides. You will get

t - 3 = 45+%2B+%28t%2F12%29+%2B+%284%2F12%29+-+30  ====>

t+-+t%2F12 = 45+%2B+%284%2F12%29+-+30+%2B+3  ====>  %2811%2F12%29%2At = 18 4%2F12 = 18 1%2F3 = {{55/3}}}  ====>

t = 12%2F11.55%2F3 = 20 minutes

Answer. The current time is 9:20 am.


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            ***** SOLVED *****
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To get familiar with the subject, see the lesson
    - Clock problems
in this site.


Also,  you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lesson is the part of this online textbook under the topic
"Travel and Distance problems".