SOLUTION: Suppose $f$ is a polynomial such that $f(0) = 47$, $f(1) = 32$, $f(2) = -13$, and $f(3)=16$. What is the sum of the coefficients of $f$?

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Suppose $f$ is a polynomial such that $f(0) = 47$, $f(1) = 32$, $f(2) = -13$, and $f(3)=16$. What is the sum of the coefficients of $f$?      Log On


   

Question 1091544: Suppose $f$ is a polynomial such that $f(0) = 47$, $f(1) = 32$, $f(2) = -13$, and $f(3)=16$. What is the sum of the coefficients of $f$?
Answer by ikleyn(52915) About Me  (Show Source):
You can put this solution on YOUR website!
.
The sum of coefficients (taken with their signs) of ANY polynomial f(x) is equal to f(1),

or 32 in your case.

All the other information in this post is unnecessary and is intendent only to confuse the reader.


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Hey,
since you post a lot of problems to the forum,

may I ask you to post them in different, readable format ?


I mean plain txt-format, commonly used in this forum.

Thank you.