SOLUTION: Hi I am using the power rule to find the derivative of f(x)= sqrt (x)
I know it goes:
f(x)= sqrt(x)
=x^1/2
=1/2x^1/2-2/2
=1/2×^-1/2
=1/ 2sqrt(x)
My question is why when I tu
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-> SOLUTION: Hi I am using the power rule to find the derivative of f(x)= sqrt (x)
I know it goes:
f(x)= sqrt(x)
=x^1/2
=1/2x^1/2-2/2
=1/2×^-1/2
=1/ 2sqrt(x)
My question is why when I tu
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Question 1091524: Hi I am using the power rule to find the derivative of f(x)= sqrt (x)
I know it goes:
f(x)= sqrt(x)
=x^1/2
=1/2x^1/2-2/2
=1/2×^-1/2
=1/ 2sqrt(x)
My question is why when I turn the exponent into a square root do I lose the negative ? Shouldnt the answer be 1/ 2sqrt(-x)?
Thanks Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! f(x)= sqrt(x)
=x^1/2
=1/2x^1/2-2/2
=1/2×^-1/2
=1/ 2sqrt(x)
My question is why when I turn the exponent into a square root do I lose the negative ? Shouldnt the answer be 1/ 2sqrt(-x)?
Thanks
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The answer is, no, it's not sqrt(-x).
It's =1/(2sqrt(x))
