SOLUTION: From a balloon 3 km high, the angles of depression to two buildings in line and on the same side of the balloon are 82 degrees and 12 degrees. How far apart are the buildings?

Algebra ->  Trigonometry-basics -> SOLUTION: From a balloon 3 km high, the angles of depression to two buildings in line and on the same side of the balloon are 82 degrees and 12 degrees. How far apart are the buildings?      Log On


   



Question 1091499: From a balloon 3 km high, the angles of depression to two buildings in line and on the same side of the balloon are 82 degrees and 12 degrees. How far apart are the buildings?
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
If this is drawn, alternate interior angles allow the same problem to be the angle of elevation to the balloon from each building.
from the closer building, tan 82=3km/distance to point below balloon.
distance=3/tan 82=0.42 km.
For the further building, distance=3/tan 12=14.11 km to point below balloon.
The two buildings are 13.69 km apart