SOLUTION: How many sides are there in a polygon if the sum of the interior angles is
a) equal to the sum of the exterior angles
b) double the sum of the exterior angles
c) 5 times the su
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-> SOLUTION: How many sides are there in a polygon if the sum of the interior angles is
a) equal to the sum of the exterior angles
b) double the sum of the exterior angles
c) 5 times the su
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Question 1091456: How many sides are there in a polygon if the sum of the interior angles is
a) equal to the sum of the exterior angles
b) double the sum of the exterior angles
c) 5 times the sum of the exterior angles? Found 2 solutions by Boreal, Alan3354:Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! Sum=(n-2)*180
exterior angle sum is always 360.
a. (n-2)*180=360; n-2=2; n=4. A square.
b. (n-2)*180=720; n-2=4; n=6. A hexagon.
c. (n-2)*180=1800; n-2=10; n=12. A dodecagon.
You can put this solution on YOUR website! How many sides are there in a polygon if the sum of the interior angles is
a) equal to the sum of the exterior angles = 360 degs
4
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b) double the sum of the exterior angles = 720 degs
Sum = 180*(n-2) = 720
n-2 = 4
n = 6
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c) 5 times the sum of the exterior angles?
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Do it like b above.
