SOLUTION: A 50%sulfuric acid solution is to be mixed with a 75% sulfuric acid solution to get 60 liters of a 60% sulfuric acid solution . How many liters of the 50% solution and the 75% solu
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Question 1091191: A 50%sulfuric acid solution is to be mixed with a 75% sulfuric acid solution to get 60 liters of a 60% sulfuric acid solution . How many liters of the 50% solution and the 75% solution should be mixed Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! Let = liters of 50% solution needed
Let = liters of 75% solution needed
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(1)
(2)
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(2)
Multiply both sides of (1) by and
subtract (1) from (2)
(2)
(1)
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and
(1)
(1)
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36 liters of 50% solution are needed
24 liters of 75% solution are needed
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check:
OK
