SOLUTION: please help me solve this find the slope and ordinate at the origin of the following equations of straight lines. a) y= 3x+2 b) 3y= -6x+3

Algebra ->  Graphs -> SOLUTION: please help me solve this find the slope and ordinate at the origin of the following equations of straight lines. a) y= 3x+2 b) 3y= -6x+3      Log On


   

Question 1091138: please help me solve this
find the slope and ordinate at the origin of the following equations of straight lines.
a) y= 3x+2
b) 3y= -6x+3
Answer by ikleyn(52794) About Me  (Show Source):
You can put this solution on YOUR website!
.
This is the rule to MEMORIZE: 

          If the straight line is presented by an equation y = ax + b,
          then the slope is equal to "a", the coefficient at x.

Now apply this rule to your equations: 

a)  y = 3x + 2.   The coefficient at "x" is 3.  Hence, the slope is 3.



b)  3y = -6x + 3.

    Divide both side by 3. You will get

    y = -2x + 1.  The coefficient at "x" is -2.  Hence, the slope is -2.

Solved.


The lesson to learn and to memorize from this solution: 

          If the straight line is presented by an equation y = ax + b,
          then the slope is equal to "a",  the coefficient at x.