SOLUTION: A rubber ball is dropped on a hard surface from a height of 80 feet and bounces up and down. On each rebound, it bounces up exactly one-half the distance it just came down. How far
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-> SOLUTION: A rubber ball is dropped on a hard surface from a height of 80 feet and bounces up and down. On each rebound, it bounces up exactly one-half the distance it just came down. How far
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Question 1091027: A rubber ball is dropped on a hard surface from a height of 80 feet and bounces up and down. On each rebound, it bounces up exactly one-half the distance it just came down. How far will the ball have traveled if you catch it after it reaches the top of the seventh bounce?
*This is a Geometric Series question. Answer by Edwin McCravy(20054) (Show Source):
The rubber ball goes down and then up seven times.
During the first "down and up" it travels 80 feet down plus
40 feet up, so the first term is 80+40 or 120 feet.
The formula for the sum of n terms is:
with n=7, a1=120, r=.
feet.
Edwin
