SOLUTION: Jenna took a jog through the park. She ran at 3 m/s for the first five minutes, and then got tired and jogged at 1 m/s for the last 2 minutes. What was her average velocity over

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Question 1091023: Jenna took a jog through the park. She ran at 3 m/s for the first five minutes, and then got tired and jogged at 1 m/s for the last 2 minutes. What was her average velocity over the entire trip home?
Found 2 solutions by jorel1380, josgarithmetic:
Answer by jorel1380(3719) About Me  (Show Source):
You can put this solution on YOUR website!
3 m/s x 5 min=3 m/s x 300 sec=900 meters
1 m/s x 2 min=1 m/s x 120 sec=120 meters
1020m/420sec= 2.43 m/s average velocity
☺☺☺☺

Answer by josgarithmetic(39627) About Me  (Show Source):
You can put this solution on YOUR website!
Distance:
3%2A5%2A60%2B120
900%2B120
1020%2Am

Time: 5%2Aminutes%2B120%2Aseconds
300%2B120seconds
420%2Aseconds


SPEED: %281020%2F420%29%28m%2Fseconds%29
2.4%28meters%2Fsecond%29