SOLUTION: solve for x in 2^(2x+1)-1/8=1/32

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Question 1090985: solve for x in 2^(2x+1)-1/8=1/32
Answer by Alan3354(69443) About Me  (Show Source):
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solve for x in 2^(2x+1)-1/8=1/32
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2^(2x+1)-1/8=1/32
2^(2x+1) = 1/32 + 1/8 = 5/32
32*2^(2x+1) = 5
2^5*2^(2x+1) = 5
2^(2x+6) = 5
(2x+6)*log(2) = log(5)
2x+6 = log(5)/log(2)
2x = -6 + log(5)/log(2)
x = -3 + ((log(5)/log(2))/2
x =~ -1.839