Notice how I edited your input using parentheses 3*sqrt(2x^2-10) to make your formula readable . . .
1. The number 3 together with its neighborhood lies in the domain of the given function.
2. In addition, the function is continuous at the poin x= 3.
3. Therefore, you can simply substitute the value x= 3 into the function to get its limit as x approaches 3:
lim = = = = .
x-->3