SOLUTION: can someone help me with this? Convert y=3*2^x to the continuous model y=Pe^rx (round r=0.0001) Convert y=32*e^0.15x to the standard model y=ab^x (round b=0.0001) Thank you

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: can someone help me with this? Convert y=3*2^x to the continuous model y=Pe^rx (round r=0.0001) Convert y=32*e^0.15x to the standard model y=ab^x (round b=0.0001) Thank you       Log On


   

Question 1090834: can someone help me with this?
Convert y=3*2^x to the continuous model y=Pe^rx (round r=0.0001)
Convert y=32*e^0.15x to the standard model y=ab^x (round b=0.0001)
Thank you
Answer by MathTherapy(10557) About Me  (Show Source):
You can put this solution on YOUR website!

can someone help me with this?
Convert y=3*2^x to the continuous model y=Pe^rx (round r=0.0001)
Convert y=32*e^0.15x to the standard model y=ab^x (round b=0.0001)
Thank you 
matrix%281%2C3%2C+y%2C+%22=%22%2C+3%282%29%5Ex%29
matrix%281%2C3%2C+y%2C+%22=%22%2C+P%28e%5Er%29%5Ex%29%29 <======== Compare the above to this
As seen, matrix%281%2C3%2C+2%2C+%22=%22%2C+e%5Er%29
matrix%281%2C3%2C+r%2C+%22=%22%2C+ln+%282%29%29 ----------- Converting to LOGARITHMIC (Natural) form
matrix%281%2C3%2C+r%2C+%22=%22%2C+0.693147181%29, so 
I take it that rounding r to .0001 (as per above instructions) means that r should be rounded to 4 decimal places. 


matrix%281%2C3%2C+y%2C+%22=%22%2C+32%28e%5E0.15%29%5Ex%29
matrix%281%2C3%2C+y%2C+%22=%22%2C+a%28b%29%5Ex%29%29 <========== Compare the above to this
As seen, matrix%281%2C3%2C+e%5E0.15%2C+%22=%22%2C+b%29
matrix%281%2C3%2C+b%2C+%22=%22%2C+1.161834243%29, so 
I take it that rounding b to .0001 (as per above instructions) means that r should be rounded to 4 decimal places.