SOLUTION: Just wanted to talk through a problem Express y in terms of x 3(log(base 6)y - 4log(base6)x) = 6 log(base6)y-log(base6)x^4 = 2 log(base6)y = log(base6)x^4 + 2 y=x^4 +2

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Just wanted to talk through a problem Express y in terms of x 3(log(base 6)y - 4log(base6)x) = 6 log(base6)y-log(base6)x^4 = 2 log(base6)y = log(base6)x^4 + 2 y=x^4 +2      Log On


   



Question 1090783: Just wanted to talk through a problem
Express y in terms of x
3(log(base 6)y - 4log(base6)x) = 6
log(base6)y-log(base6)x^4 = 2
log(base6)y = log(base6)x^4 + 2
y=x^4 +2

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Express y in terms of x
3(log(base 6)y - 4log(base6)x) = 6
log(base6)y-log(base6)x^4 = 2
---------------
3log%286%2Cy%29+-+4log%286%2Cx%29+=+2
log%286%2Cy%5E3%29+-+log%286%2Cx%5E4%29+=+log%286%2C6%5E2%29
log%286%2Cy%5E3%29+=+log%286%2Cx%5E4%29+%2B+log%286%2C6%5E2%29
log%286%2Cy%5E3%29+=+log%286%2C36%2Ax%5E4%29
y%5E3+=+36%2Ax%5E4
y+=+x%2Aroot%283%2C36x%29