SOLUTION: Tim and Jeff have some money. If Jeff gives $5 to Tim, then they will have the same amount of money. If Tim gives $5 to Jeff, then Jeff would have twice as much as Tom. how much

Algebra ->  Equations -> SOLUTION: Tim and Jeff have some money. If Jeff gives $5 to Tim, then they will have the same amount of money. If Tim gives $5 to Jeff, then Jeff would have twice as much as Tom. how much      Log On


   



Question 1090755: Tim and Jeff have some money. If Jeff gives $5 to Tim, then they will have the same amount of money.
If Tim gives $5 to Jeff, then Jeff would have twice as much as Tom. how much money does each have at first?

Found 2 solutions by ikleyn, jorel1380:
Answer by ikleyn(52756) About Me  (Show Source):
You can put this solution on YOUR website!
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Tim and Jeff have some money. If Jeff gives $5 to Tim, then they will have the same amount of money.
If Tim gives $5 to Jeff, then Jeff would have twice as much as Tom. how much money does each have at first?
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Let Tim has T dollars, and let Jeff has J dollars.

If Jeff gives $5 to Tim, Jeff will have (J-5) dollars, while Tim will have (T+5) dollars.


According to the condition, these amounts are identical, which gives you an equation

J - 5 = T + 5.       (1)


If in opposite, Tim gives $5 to Jeff, Tim will have (T-5) dollars, while Jeff will have (J+5) dollars.

According to the condition, in this case you obtain this equation

J + 5 = 2*(T-5).     (2)


The equations (1) and (2) form the system of two equations for two unknowns.

From (2), express J = T + 5 + 5 = T + 10 and substitute it into (2), replacing J:

(T+10) + 5 = 2*(T-5),

T + 15 = 2T - 10,

10 + 15 = T  ====>  T = 25.


Answer.  Tim has $25.   Jeff has T+10 = 25 + 10 = 35 dollars.


Answer by jorel1380(3719) About Me  (Show Source):
You can put this solution on YOUR website!
Let t and j be Tim's money and Jeff's money, respectively. Then:
j-5=t+5
j+5=2(t-5)
So:
j=t+10
t+10+5=2t-10
t=25
j=35
Tim has $25; Jeff has $35
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