SOLUTION: A 575 meter long train crosses a tunnel of 325 meter in 90 sec. What is the speed of the train in km/h?

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Question 1090428: A 575 meter long train crosses a tunnel of 325 meter in 90 sec. What is the speed of the train in km/h?

Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
  

Assume that the train is moving from left to right in
the drawing above.

The front of the train begins at B and must travel to D.
So the front of the train travels the distance of BD in
order for the entire train to be completely out of the 
tunnel.

BD = BC + CD = 325 + 575 = 900 meters.

[Note that you could also do it by saying that the end
of the train begins at A and must travel to C.
So the end of the train travels the distance of AC in
order to be completely out of the tunnel. 

AC = AB + BC = 575 + 325 = 900 meters.]

SPEED%22%22=%22%22DISTANCE%2FTIME

The Distance is 900 meters and the Time = 90 seconds

SPEED%22%22=%22%22matrix%281%2C2%2C900%2Cmeters%29%2Fmatrix%281%2C2%2C90%2Cseconds%29%22%22=%22%22matrix%281%2C2%2C10%2Cm%2Fs%29

Edwin