SOLUTION: The width of a rectangle is four less than one half the length. If the perimeter of the rectangle is 94 meters, find the area of the rectangle. For this I have to solve the equatio

Algebra ->  Trigonometry-basics -> SOLUTION: The width of a rectangle is four less than one half the length. If the perimeter of the rectangle is 94 meters, find the area of the rectangle. For this I have to solve the equatio      Log On


   

Question 1090350: The width of a rectangle is four less than one half the length. If the perimeter of the rectangle is 94 meters, find the area of the rectangle. For this I have to solve the equation but I'm not sure how to make the equation. I have Width - 4 = 1/2 the length and I have that the perimeter is 94 I really need some help.
Answer by josgarithmetic(39615) About Me  (Show Source):
You can put this solution on YOUR website!
w for width
L for length
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width of a rectangle is four less than one half the length.
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w=L%2F2-4

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the perimeter of the rectangle is 94 meters,
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2L%2B2w=94
2L%2B2%28L%2F2-4%29=94
2L%2BL-8=94
3L=94%2B8
3L=102
highlight%28L=34%29
-
highlight%28w=13%29

You can evaluate the area, w%2AL.