SOLUTION: 2x^2-x-3 over 3x^2+7x+4 multiplied by 3x^2-11x-20 over 4x^2-9. In the first part I factored it down to (2x-3)(x+1)over (x+1)(3x+4, then cancelled the (x-1) to have (2x-3)over(3x+4)
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-> SOLUTION: 2x^2-x-3 over 3x^2+7x+4 multiplied by 3x^2-11x-20 over 4x^2-9. In the first part I factored it down to (2x-3)(x+1)over (x+1)(3x+4, then cancelled the (x-1) to have (2x-3)over(3x+4)
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Question 109032: 2x^2-x-3 over 3x^2+7x+4 multiplied by 3x^2-11x-20 over 4x^2-9. In the first part I factored it down to (2x-3)(x+1)over (x+1)(3x+4, then cancelled the (x-1) to have (2x-3)over(3x+4)ramaining. However in the second part I factored the top down to (x-5)(3x+4)but I do not know what to do with the bottom part (4x^2-9). Can you help me with the rest, if I got the first part correct?
This is from Pre-Algebra by Hutchison 6th edition chapter 5.2 Answer by scott8148(6628) (Show Source):
