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factor (1)/(x^(2))-(1)/(x)=6
~~~~~~~~~~~~~~~~~
Introduce new variable  y =  .      (1)
Then your equation will take the form
.      (1)
Then your equation will take the form
 = 6,    or, equivalently,
 = 6,    or, equivalently,
 = 0.          (2)
The left side quadratic polynomial can be easily factored 
(y-3)*(y+2) = 0.      (3)
It gives the roots of the equation  y = 3  and  y = -2.
Let us consider both cases.
1.  If y = 3,   then  x =
 = 0.          (2)
The left side quadratic polynomial can be easily factored 
(y-3)*(y+2) = 0.      (3)
It gives the roots of the equation  y = 3  and  y = -2.
Let us consider both cases.
1.  If y = 3,   then  x =  =
 =  ,  due to (1).
2.  If y = -2,  then x =
,  due to (1).
2.  If y = -2,  then x =  =
 =  .
Answer.  The original equation has the roots
.
Answer.  The original equation has the roots   and
  and   .
.
Solved.
Notice.  The formulation of the problem in your post is not exactly adequate.
The ideally balanced formulation is  THIS:
     Solve the equation  (1)/(x^(2))-(1)/(x)=6  using factoring.