SOLUTION: x²+4x+y²-4y=-4,(x-2)²+(y-2)²=4

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Question 1090252: x²+4x+y²-4y=-4,(x-2)²+(y-2)²=4
Answer by ikleyn(52795) About Me  (Show Source):
You can put this solution on YOUR website!
.
x%5E2+%2B+4x+%2B+y%5E2+-+4y = 4,    (1)
%28x-2%29%5E2+%2B+%28y-2%29%5E2 = 4.    (2)

Open the parentheses in equation (2). You will get

x%5E2+%2B+4x+%2B+y%5E2+-+4y = 4,    (1')
x%5E2+-+4x+%2B+y%5E2+-+4y = -4.   (2')


Subtract eq(1') from eq(2') (both sides). You will get

-8x = -4 - 4 = -8.


Hence, x = 1.


Now, substitute x= 1 into either of the two equations (1') or (2') and solve for y.


Can you complete these simple calculations on your own ?

For many similar solved problems/samples see the lesson
    - Solving the system of algebraic equations of degree 2,
in this site.


Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lesson is the part of this online textbook under the topic "Systems of equations that are not linear".