SOLUTION: what is the maximum value for the function f(x)=4x^2-8x+16^?

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Question 1090251: what is the maximum value for the function f(x)=4x^2-8x+16^?
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
None. No maximum value unless you have a specific interval. Your parabola has a minimum value.

y=4%28x%5E2-2x%2B4%29
y=4%28x%5E2-2x%2B1-1%2B4%29
4%28%28x-1%29%5E2%2B3%29
4%28x-1%29%5E2%2B12

The MINIMUM value is f%281%29=highlight_green%2812%29.