SOLUTION: When 1000 is divided by some positive integer x, the remainder is 45. What is the sum of the largest and smallest value of x
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-> SOLUTION: When 1000 is divided by some positive integer x, the remainder is 45. What is the sum of the largest and smallest value of x
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Question 1090247: When 1000 is divided by some positive integer x, the remainder is 45. What is the sum of the largest and smallest value of x Answer by ikleyn(52818) (Show Source):
1. The condition is equivalent to the fact that 1000-45 = 955 is divisible by x.
2. 955 = 5*191, and both 5 and 191 are prime numbers.
3. Hence, EITHER x= 5 OR x= 191.
4. Thus 5 + 191 = 196 is the answer.
