SOLUTION: How many different four digit number can be written using the digits 1,2,3,4,5,6,7 and 8 only once such that the number 2 is contained once.

Algebra ->  Permutations -> SOLUTION: How many different four digit number can be written using the digits 1,2,3,4,5,6,7 and 8 only once such that the number 2 is contained once.       Log On


   



Question 1090200: How many different four digit number can be written using the digits 1,2,3,4,5,6,7 and 8 only once such that the number 2 is contained once.

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
By contained once I assume you mean used once so the numbers would look like
2xyz, x2yz, xy2z, xyz2 where x,y,z are unique digits not equal to 2.
So then for each case,
N=7%2A6%2A5=210
There are 4 cases as shown so the total number of digits would be,
N%5Btot%5D=4%2A210
N%5Btot%5D=840